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Re: simple triangle question. please help

Debmalya — Fri, 03 Jul 2009 11:31:34 GMT

... Area of triangle pqs = 1/2 * PR * QS ( QS being the hypotenuse of the triangle is equal to 5) Area of triangle pqs also = 1/2 * 3 * 4 hence 1/2 * 3 * 4 =

Stress management

mithunprakash_83 — Fri, 03 Jul 2009 11:29:57 GMT

... Hi Abdi could you be precise and let me know what it is that you did to work on stress and time management. I have no issues with time management but

Re: simple triangle question. please help

yosushant — Mon, 29 Jun 2009 07:54:00 GMT

... given pq = 3 ps = 4 this implies qs = 5 let qr = x this implies sr = (5-x) now pqr and psr, both are right triangles in pqr (3*3) = pr*pr + (x*x in psr

(no subject)

abdi borhan — Mon, 29 Jun 2009 07:53:50 GMT

Hi everybody, I'm Abdi. I've taken the GMAT twice, but unfortunately I couldn't gain the score I need for the B-schools. So, I've decided to make another

Re: How to apply for GMAT

mithun prakash — Thu, 25 Jun 2009 07:28:55 GMT

Btw make sure ur details match with ur passport. Ur name, address and other important details shuld be exactly the same as it is on your passport.. If there is

Re: simple triangle question. please help [1 Attachment]

Saleng — Thu, 25 Jun 2009 07:27:43 GMT

area = 3 * 4 / 2 = 6 area = QS * PR / 2 PR = area * 2 / PR = 6 * 2 / 5 = 12/5 2009/5/31 Thomas Meade

Re: vocabulary...!

Michelle Bakunoff — Thu, 25 Jun 2009 07:26:11 GMT

No not at all Sent from my iPhone On Jun 6, 2009, at 6:01 AM, "bala_2199" wrote: is it necessary to prepare lots of vocabulary for gmat

Re: Sentence Correction problem

Kevin Poornendulal — Mon, 15 Jun 2009 05:40:23 GMT

subjunctive mood is true but there is another reason that holds good for C being the correct answer. Please correct me if I am wrong. a portion of capital -

Re: simple triangle question. please help

shyam_kkumar — Mon, 15 Jun 2009 05:39:56 GMT

The area of the triangle is 1/2 x QP x PS Another way for calculating the area is 1/2 x QS x PR. Simply by equating above two areas we can get the answer.

Re: simple triangle question. please help [1 Attachment]

Vamsi Rao — Mon, 15 Jun 2009 05:39:55 GMT

It is B : 12/5 how :- Let PR=y Let QR=x as per right angl trngl PQS (PQ)^2 + (PS)^2=(QS)^2 3^2 + 4^2=9+16=25 = (5)^2= (QS)^2 ie QS=5 Also PQR and PRS are

Re: simple triangle question. please help [1 Attachment]

ravi — Mon, 15 Jun 2009 05:39:19 GMT

You can solve this by: 1) Calc PR^2 from 2 triangle PQR and PRS (assuming RS = x so QR will be 5-x) 2) Then equate both i.e. PR^2 from 1st triangle =

Re: How to apply for GMAT

anirudh babbar — Mon, 15 Jun 2009 05:37:55 GMT

If u want to apply for gmat , u should visit www.mba.com official website of gmat . fees is 250 $ . rest about schedules of examination u can refer to the

vocabulary...!

bala_2199 — Mon, 15 Jun 2009 05:37:34 GMT

is it necessary to prepare lots of vocabulary for gmat as we do for gre... please reply.. wats the amount of vocab we need to have,...

Re: simple triangle question. please help [1 Attachment]

Satya Ramesh — Mon, 15 Jun 2009 05:37:30 GMT

This is a nice question thomas. Using pythogorous theorem, we know QS=5. Lets assume QR=x, then RS=(5-x). Let PR=y. Since QRP & SRP are right angle

How to apply for GMAT

vikrambakshi67 — Sat, 06 Jun 2009 04:47:57 GMT

Kindly advise how to apply for appearing GMAT exam, when should i apply if i want to appear in AUg/Sep 09. What will be the cost. Also i have some material on