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    <title>4gmat at Yahoo! Groups</title>
    <link>http://groups.yahoo.com/group/4gmat/</link>
    <description>4gmat - GMAT Online Preparation</description>

    <item>
      <title>INSEAD MBA info</title>
      <pubDate>Sat, 23 Jan 2010 05:06:46 GMT</pubDate>
      <dc:creator>Mahaveerprabu Thangaraj</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1670</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1670</guid>
      <description>If you can&#39;t this message, please click here: </description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Thu, 07 Jan 2010 06:45:51 GMT</pubDate>
      <dc:creator>4GMAT - GMAT Classes, Discussion Forums</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1669</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1669</guid>
      <description>Hi You are right. The question has two answers. Both B and E. Error regretted. K S Baskar ... From: amir hatef To: 4gmat@yahoogroups.com Sent: Friday, January</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Wed, 06 Jan 2010 06:51:43 GMT</pubDate>
      <dc:creator>Tauseef Ahmed</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1668</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1668</guid>
      <description>So lets look at the facts.... If (x - 11)(x - 3) is negative then either 1. (x-11) is &#43;ve and (x-3) is -ve 2. (x-11) is -ve and (x-3) is &#43;ve These are only 2</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Wed, 06 Jan 2010 06:50:54 GMT</pubDate>
      <dc:creator>kanishk singh</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1667</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1667</guid>
      <description>B is the correct answer. C is definitely wrong. Try substituting x=4 for the 2 given conditions and you&#39;ll c tht it fits perfectly. It&#39;s B coz tht means the</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Wed, 06 Jan 2010 06:50:36 GMT</pubDate>
      <dc:creator>amir hatef</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1666</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1666</guid>
      <description>Hi there, Right! But also when you have assupmtion like  3&lt; x &lt;11 and x is a real number, choice (E) can be true surely. When 3&lt;x&lt;11, then 11-x&gt;0, Isn&#39;t</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Fri, 01 Jan 2010 10:36:37 GMT</pubDate>
      <dc:creator>Said Boufatis</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1665</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1665</guid>
      <description>If (x - 11)(x - 3) is negative, then x must be greater than 3 and less than 11. So, A. x^2 + 5x + 6 &lt; 0 --&gt; (x&#43;2)(x&#43;3)&lt;0 --&gt; x greater than -3 and less than -2</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Fri, 01 Jan 2010 10:35:18 GMT</pubDate>
      <dc:creator>Dilip Chaturvedi</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1664</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1664</guid>
      <description>option : C Kind Regards, Dilip Chaturvedi Mobile:09930742625 ________________________________ From: &quot;4GMAT - GMAT Classes, Discussion Forums&quot;</description>
    </item>
    <item>
      <title>Re: Inequalities / Quadratic Equation</title>
      <pubDate>Fri, 01 Jan 2010 10:34:52 GMT</pubDate>
      <dc:creator>Amit Mathur</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1663</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1663</guid>
      <description>Should be B&amp;E but if I have to choose one it should be E                  (x - 11)(x - 3) x&lt; 0             + VE x&gt;0</description>
    </item>
    <item>
      <title>Inequalities / Quadratic Equation</title>
      <pubDate>Wed, 30 Dec 2009 06:23:33 GMT</pubDate>
      <dc:creator>4GMAT - GMAT Classes, Discussion Forums</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1662</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1662</guid>
      <description>Which of the following is correct if x is a real number and (x - 11)(x - 3) is negative? A. x^2 + 5x + 6 &lt; 0 B. x^2 + 5x + 6 &gt; 0 C. 5 - x &lt; 0 D. x - 5 &lt; 0 E.</description>
    </item>
    <item>
      <title>R2, R3 deadline US B schools : Ready Reckoner</title>
      <pubDate>Sat, 19 Dec 2009 11:59:40 GMT</pubDate>
      <dc:creator>4GMAT - GMAT Classes, Discussion Forums</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1661</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1661</guid>
      <description>Hi Here is a quick reckoner of R2 and R3 deadlines and admission notification of top 20 odd US B Schools. </description>
    </item>
    <item>
      <title>Deadlines for European and Asian B Schools 2010</title>
      <pubDate>Thu, 17 Dec 2009 03:50:57 GMT</pubDate>
      <dc:creator>4GMAT - GMAT Classes, Discussion Forums</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1660</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1660</guid>
      <description>Hi If you have missed the R1 deadlines of US B Schools and have not started your preparation for R2 deadlines of US B Schools and will still like to start your</description>
    </item>
    <item>
      <title>Re: Critical Reasoning Question</title>
      <pubDate>Wed, 02 Dec 2009 10:46:26 GMT</pubDate>
      <dc:creator>Aditya Dutta</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1659</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1659</guid>
      <description>Hi, The answer to this has to be &#39;D&#39;. - The argument here is whether the paint can withstand changes in the temp and humidity.- In the first part, the</description>
    </item>
    <item>
      <title>Re: Critical Reasoning Question</title>
      <pubDate>Wed, 02 Dec 2009 10:43:29 GMT</pubDate>
      <dc:creator>adutta_bea</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1658</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1658</guid>
      <description>The answer to this has to be &#39;D&#39;. - The argument here is whether the paint can withstand changes in the temp and humidity. - In the first part, the judgement</description>
    </item>
    <item>
      <title>Re: Converting Percentiles to Real GMAT Scorews</title>
      <pubDate>Wed, 02 Dec 2009 10:42:44 GMT</pubDate>
      <dc:creator>abdi borhan</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1657</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1657</guid>
      <description>DearAmrit, Percentiles at the end of the official guide only indicate the percentage of people below you. Regards Abdi ________________________________ From:</description>
    </item>
    <item>
      <title>Re: Critical Reasoning Question</title>
      <pubDate>Wed, 02 Dec 2009 10:42:13 GMT</pubDate>
      <dc:creator>Satya Ramesh</dc:creator>
      <link>http://groups.yahoo.com/group/4gmat/message/1656</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/4gmat/message/1656</guid>
      <description>I believe the answer is B. The first bold statement is a position &amp; not an objection, judgement or claim.  Satya Ramesh Vemuri www.twitter.com/vsatyaramesh </description>
    </item>

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