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    <title>GraphingCalcUsers at Yahoo! Groups</title>
    <link>http://groups.yahoo.com/group/GraphingCalcUsers/</link>
    <description>User group for Pacific Tech&#39;s Graphing Calculator math education visualization software</description>

    <item>
      <title>Hypercube projected onto diagonal hyperplane. Generalized cross-prod</title>
      <pubDate>Mon, 06 May 2013 10:09:17 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1978</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1978</guid>
      <description>The projection of a cube onto the diagonal plane specified by x + y + z = 0 will yield a hexagon with each of the parallelograms taking up two segments. </description>
    </item>
    <item>
      <title>Vector function for oblique projections. Restricting test point to z</title>
      <pubDate>Wed, 01 May 2013 12:47:05 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1977</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1977</guid>
      <description>If we restrict the test point to the z = 0 plane, then we have the same coordinates for its projection in the projected grid, as we&#39;d expect for a linear</description>
    </item>
    <item>
      <title>Oblique projection onto plane, vector function</title>
      <pubDate>Wed, 01 May 2013 12:41:07 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1976</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1976</guid>
      <description>This is based on the derivation at http://math.stackexchange.com/questions/117418/projection-to-the-plane-in-the-direction-of-the-vector</description>
    </item>
    <item>
      <title>Gram-Schmidt orthogonalization. Shortcut via projection onto plane.</title>
      <pubDate>Fri, 12 Apr 2013 18:39:02 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1975</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1975</guid>
      <description>Here, we streamline the orthogonalization by using the formula for projection onto the plane determined by unit vectors u and v: We use the matrix identity . </description>
    </item>
    <item>
      <title>Orthogonalization of a basis (Gram-Schimidt and adapted)</title>
      <pubDate>Wed, 10 Apr 2013 17:11:57 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1974</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1974</guid>
      <description>If we use the matrix-product versions of projections onto a line and a plane, we save some computation. It&#39;s also visually clearer. We Just back off on each</description>
    </item>
    <item>
      <title>Non-square matrices used to both embed and detach a vector mapping, </title>
      <pubDate>Tue, 09 Apr 2013 05:15:38 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1973</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1973</guid>
      <description>[I forgot to include the expressions for the circles and dots in the previous posting.] Below, I&#39;ve used non-square matrices in two ways: once, via , to map</description>
    </item>
    <item>
      <title>Non-square matrices used to both embed and detach a vector mapping</title>
      <pubDate>Tue, 09 Apr 2013 05:11:29 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1972</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1972</guid>
      <description>Below, I&#39;ve used non-square matrices in two ways: once, via , to map the gray circle in the 2D view to the slanted plane in the 3D view, and secondly, via the</description>
    </item>
    <item>
      <title>Visualizing non-square matrices, cont. Embedding in a sub-space.</title>
      <pubDate>Mon, 08 Apr 2013 14:04:37 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1971</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1971</guid>
      <description>[OK, I got a little carried away by my frustration at the total lack of interest I&#39;m getting from everyone on what I think are exciting discoveries. Not</description>
    </item>
    <item>
      <title>Visualizing non-square matrices, cont.</title>
      <pubDate>Mon, 08 Apr 2013 13:59:26 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1970</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1970</guid>
      <description>Non-square matrices are either &quot;embedding&quot; or &quot;detaching&quot; mappings. This one, , takes the vector that follows and &quot;embeds&quot; it in the subspace of xyz-space</description>
    </item>
    <item>
      <title>Vector geometry of Gram-Schmidt procedure in 3D</title>
      <pubDate>Wed, 03 Apr 2013 14:38:54 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1969</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1969</guid>
      <description>The idea is that we have to prevent each succeeding vector from projecting on any of the previously orthogonalized vectors. Then we&#39;re guaranteed to have an</description>
    </item>
    <item>
      <title>Re: Arc and quadrants [1 Attachment]</title>
      <pubDate>Fri, 22 Mar 2013 14:18:16 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1968</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1968</guid>
      <description>... If you just want the small angle between vectors drawn from the origin, it&#39;s enough to use . But, even then, we&#39;ve got to correct for the case when the</description>
    </item>
    <item>
      <title>Functional equations for trig functions</title>
      <pubDate>Fri, 22 Mar 2013 14:13:30 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1967</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1967</guid>
      <description>Actually, maybe it&#39;s more intuitive to get our definitions of the inner and outer products (= determinant, in the 2D case) from the projection functions we use</description>
    </item>
    <item>
      <title>Determinant and inner product as related to trig angle addition form</title>
      <pubDate>Fri, 22 Mar 2013 14:07:53 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1966</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1966</guid>
      <description>The determinant formula and the inner product formula (in 2D Euclidean space) together form 2 functional equations which I think uniquely specify the sine and</description>
    </item>
    <item>
      <title>Arc function. Relation of determinant to sign of angle. Determinant </title>
      <pubDate>Fri, 22 Mar 2013 12:51:03 GMT</pubDate>
      <dc:creator>Christopher Young</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1965</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1965</guid>
      <description>The determinant  always equals . This can be seen from the diagram above, where the length of MB times the length of VA gives the area of the parallelogram on</description>
    </item>
    <item>
      <title>Arc and quadrants</title>
      <pubDate>Fri, 22 Mar 2013 10:24:11 GMT</pubDate>
      <dc:creator>Bo Johannesson</dc:creator>
      <link>http://groups.yahoo.com/group/GraphingCalcUsers/message/1964</link>
      <guid isPermaLink="true">http://groups.yahoo.com/group/GraphingCalcUsers/message/1964</guid>
      <description>Hej! I have made a document which illustrates two vectors in the x,y-plane and the angle between them. The way I do to plot the arc between the vectors is</description>
    </item>

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