http://tech.groups.yahoo.com/group/magiccubes/ magiccubes Mon, 14 Aug 2006 23:34:10 GMT Ant http://tech.groups.yahoo.com/group/magiccubes/message/235 http://tech.groups.yahoo.com/group/magiccubes/message/235 ...managed to answer my own Question... Magic Cubes have the same pattern of constant sharing as Magic Squares, but with a lower start number. i.e. Magic Fri, 11 Aug 2006 19:39:26 GMT Ant http://tech.groups.yahoo.com/group/magiccubes/message/234 http://tech.groups.yahoo.com/group/magiccubes/message/234 I have been looking into the sharing properties of magic squares sharing constant values and found them fascinating. Can anyone direct me to a site that covers Tue, 01 Aug 2006 10:30:00 GMT Ant http://tech.groups.yahoo.com/group/magiccubes/message/233 http://tech.groups.yahoo.com/group/magiccubes/message/233 Have you seen a magic 4 cube with 198 start number? http://www.mysticalwonders.org/group/viewtopic.php?t=2371 There are three constants of 64 between each Tue, 01 Aug 2006 02:50:41 GMT xoet@... http://tech.groups.yahoo.com/group/magiccubes/message/232 http://tech.groups.yahoo.com/group/magiccubes/message/232 In a message dated 7/31/2006 5:32:19 P.M. Eastern Standard Time, ant@... writes: w3 + x3 + y3 = z3 Mon, 31 Jul 2006 21:31:22 GMT Ant http://tech.groups.yahoo.com/group/magiccubes/message/231 http://tech.groups.yahoo.com/group/magiccubes/message/231 w3 + x3 + y3 = z3 http://www.earthmatrix.com/serie56/maya56.htm ... From: Bill Newbold To: magiccubes@yahoogroups.com Sent: Monday, July 31, 2006 2:37 PM Mon, 31 Jul 2006 13:39:50 GMT Bill Newbold http://tech.groups.yahoo.com/group/magiccubes/message/230 http://tech.groups.yahoo.com/group/magiccubes/message/230 hello, I wrote a program that solved for x, y, z and found r as a whole number for the equation above there were many unique answers just by looping through x, Sun, 07 Aug 2005 15:22:00 GMT sterten@... http://tech.groups.yahoo.com/group/magiccubes/message/224 http://tech.groups.yahoo.com/group/magiccubes/message/224 My computer searched pandiagonal symmetric latin squares of size 17. Atkin, Hay, Larsen had enumerated pandiagonal latin squares (PLS) of order 13 in 1982 by Thu, 03 Mar 2005 16:01:39 GMT sterten@... http://tech.groups.yahoo.com/group/magiccubes/message/223 http://tech.groups.yahoo.com/group/magiccubes/message/223 In einer eMail vom 03.03.2005 16:38:44 Westeuropäische Normalzeit schreibt ... yes, you can make this strictly axiomatically. In set-theory you have an axiom Thu, 03 Mar 2005 15:34:56 GMT Abhinav Soni http://tech.groups.yahoo.com/group/magiccubes/message/222 http://tech.groups.yahoo.com/group/magiccubes/message/222 I mean that by common sense one can say that 2.17 is not an integer but is there any way to prove this mathematically. ... __________________________________ Thu, 03 Mar 2005 13:32:35 GMT sterten@... http://tech.groups.yahoo.com/group/magiccubes/message/221 http://tech.groups.yahoo.com/group/magiccubes/message/221 Dear Sony, ... you'll find this in standard math-books, or search google for "peano axioms" ... the equation itself isn't conscious. You must specify what Thu, 03 Mar 2005 12:03:14 GMT Abhinav Soni http://tech.groups.yahoo.com/group/magiccubes/message/220 http://tech.groups.yahoo.com/group/magiccubes/message/220 Dear all, This might look absurd but what is an integer? How do you define an integer? As magic squares and cubes have only integers. All the equations Sat, 19 Feb 2005 05:27:51 GMT sterten2000 http://tech.groups.yahoo.com/group/magiccubes/message/219 http://tech.groups.yahoo.com/group/magiccubes/message/219 I was trying to get this paper: http://scitation.aip.org/getabs/servlet/GetabsServlet? prog=normal&id=AJPIAS000072000006000786000001&idtype=cvips&gifs=yes but Sat, 18 Dec 2004 06:34:12 GMT sterten@... http://tech.groups.yahoo.com/group/magiccubes/message/214 http://tech.groups.yahoo.com/group/magiccubes/message/214 here is my C-programm which backtracks through all magic cubes of size 3 in 17 seconds on my Computer. Note, that the cells are in filled in order P[], so to Fri, 17 Dec 2004 16:48:38 GMT Someone Somebody http://tech.groups.yahoo.com/group/magiccubes/message/213 http://tech.groups.yahoo.com/group/magiccubes/message/213 ... Thanks for the solution, but one day before I wrote this message, I had sent the project (magic cubes) to my teacher. And you know what... he gave me a C-, Wed, 15 Dec 2004 15:52:37 GMT sterten@... http://tech.groups.yahoo.com/group/magiccubes/message/211 http://tech.groups.yahoo.com/group/magiccubes/message/211 ... I don't want to walk through the source, but now I see, what the problem is: find all 3*3*3 magic cubes filled with integers 1..27 (normal) with a