http://tech.groups.yahoo.com/group/mathforfun/ MATH for FUN - A place to post and work math problems. Tue, 30 Jun 2009 21:40:36 GMT abelov0927 http://tech.groups.yahoo.com/group/mathforfun/message/13731 http://tech.groups.yahoo.com/group/mathforfun/message/13731 Thank you for this explanation. It's good. I'm trying to find out the platform finish line velocity. I'm sure it'll close to zero, but the platform may not Tue, 30 Jun 2009 17:39:31 GMT video_ranger http://tech.groups.yahoo.com/group/mathforfun/message/13730 http://tech.groups.yahoo.com/group/mathforfun/message/13730 Correction: I meant positive forward velocity V=(nm/(M+nm))v. Tue, 30 Jun 2009 17:34:27 GMT video_ranger http://tech.groups.yahoo.com/group/mathforfun/message/13729 http://tech.groups.yahoo.com/group/mathforfun/message/13729 ... If the platform is completely free to move (say floating in outer space) momentum conservation requires that it will end up with a positive forward Tue, 30 Jun 2009 15:56:50 GMT abelov0927 http://tech.groups.yahoo.com/group/mathforfun/message/13728 http://tech.groups.yahoo.com/group/mathforfun/message/13728 By 'model', I just want to describe behavior of this system. All laws of classical mechanic should be preserved. Initial platform velocity is zero V0=0. Will Tue, 30 Jun 2009 15:47:45 GMT video_ranger http://tech.groups.yahoo.com/group/mathforfun/message/13727 http://tech.groups.yahoo.com/group/mathforfun/message/13727 OK I didn't realize the ring was a flexible chain. That makes it more complex than a rigid ring. Yes if the surface has initial velocity V=0 but can move Tue, 30 Jun 2009 14:27:57 GMT abelov0927 http://tech.groups.yahoo.com/group/mathforfun/message/13726 http://tech.groups.yahoo.com/group/mathforfun/message/13726 I recieved empty reply from Rich-Text Editor (Beta). Tue, 30 Jun 2009 14:23:49 GMT abelov0927 http://tech.groups.yahoo.com/group/mathforfun/message/13725 http://tech.groups.yahoo.com/group/mathforfun/message/13725 I'll repost message in new way. The idea is very simple. If spit a rolling ring to small parts set of n elements (1,2,3,...,n) with mass m then each of them Tue, 30 Jun 2009 14:05:54 GMT video_ranger http://tech.groups.yahoo.com/group/mathforfun/message/13724 http://tech.groups.yahoo.com/group/mathforfun/message/13724 ... Yes. ... Beginning here I'm not sure what you're saying. Are you assuming the broken ring continues to roll without slipping? Are any more links going to Mon, 29 Jun 2009 18:23:10 GMT abelov0927 http://tech.groups.yahoo.com/group/mathforfun/message/13723 http://tech.groups.yahoo.com/group/mathforfun/message/13723 link to original site http://knol.google.com/k/alex-belov/paradox-of-classical-mechanics-2/1xmqm1l0s4ys/9# or mirror Wed, 17 Jun 2009 10:20:52 GMT cino hilliard http://tech.groups.yahoo.com/group/mathforfun/message/13721 http://tech.groups.yahoo.com/group/mathforfun/message/13721 Yep stevo, I got way outside the box on that one but decided to leave it as it may be useful for annuities interest rate calculation which is what I thought it Tue, 16 Jun 2009 23:38:01 GMT MorphemeAddict@... http://tech.groups.yahoo.com/group/mathforfun/message/13720 http://tech.groups.yahoo.com/group/mathforfun/message/13720 In a message dated 6/16/2009 00:34:47 Eastern Daylight Time, ... That's an awful lot of program for solving a simple algebra problem. I got the same answer in Tue, 16 Jun 2009 14:10:54 GMT Science - Technology Foundation http://tech.groups.yahoo.com/group/mathforfun/message/13719 http://tech.groups.yahoo.com/group/mathforfun/message/13719 Welcome to the SCIENCE & TECHNOLOGY mail exchange group. Join this group to collect information in SCIENCE & TECHNOLOGY issues. Provide useful and important Tue, 16 Jun 2009 14:10:27 GMT Deepak Mehra http://tech.groups.yahoo.com/group/mathforfun/message/13718 http://tech.groups.yahoo.com/group/mathforfun/message/13718 ________________________________ then do it buddy [Non-text portions of this message have been removed] Tue, 16 Jun 2009 12:18:18 GMT Sarmad Al Jameel http://tech.groups.yahoo.com/group/mathforfun/message/13717 http://tech.groups.yahoo.com/group/mathforfun/message/13717 Tue, 16 Jun 2009 12:13:45 GMT Sarmad Al Jameel http://tech.groups.yahoo.com/group/mathforfun/message/13716 http://tech.groups.yahoo.com/group/mathforfun/message/13716 ... i=[((r+1)^(1/n))-1]/n