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    <title>primeform at Yahoo! Groups</title>
    <link>http://tech.groups.yahoo.com/group/primeform/</link>
    <description>User group for PFGW &amp; PrimeForm programs</description>

    <item>
      <title>Re: New Ap6 Record</title>
      <pubDate>Thu, 19 Nov 2009 03:21:16 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9830</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9830</guid>
      <description>... Watch this space, folks. Mike&#39;s code is already rather nifty; Ken&#39;s might get even niftier. Per ardua ad astra David</description>
    </item>
    <item>
      <title>Re: New Ap6 Record</title>
      <pubDate>Thu, 19 Nov 2009 03:10:10 GMT</pubDate>
      <dc:creator>kraDen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9829</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9829</guid>
      <description>Hi Mike, ... sieved n=100,000,000-200,000,000 to 10^12 30,873,079 tests 306917 prps 147359 ap4s 335 ap5s 0 ap6s extended ap5&#39;s (up 77 and down 70) no ap6 </description>
    </item>
    <item>
      <title>Re: large Sophie</title>
      <pubDate>Thu, 19 Nov 2009 02:21:22 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9828</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9828</guid>
      <description>... And renewed congratulations, for another: http://primes.utm.edu/primes/page.php?id=90907 Where PrimeGrid and TPS failed, Minnesota, Stanford and Eötvös</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 14:39:16 GMT</pubDate>
      <dc:creator>jkcmagic</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9827</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9827</guid>
      <description>Letting f(x) be your polynomial, you can eliminate one sextic (replacing it with a quartic) by using f(5*x^3-x^2-x-1). i.e. h(x) = (x*(5*x + 9)/2 - 31)^2; d(x)</description>
    </item>
    <item>
      <title>Re: New Ap6 Record</title>
      <pubDate>Wed, 18 Nov 2009 12:42:18 GMT</pubDate>
      <dc:creator>Jens Kruse Andersen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9826</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9826</guid>
      <description>... Congratulations. http://users.cybercity.dk/~dsl522332/math/aprecords.htm is updated with the assumption that NewPGen and PrimeForm were used again. -- Jens</description>
    </item>
    <item>
      <title>Re: New Ap6 Record</title>
      <pubDate>Wed, 18 Nov 2009 08:34:46 GMT</pubDate>
      <dc:creator>mikeoakes2</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9825</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9825</guid>
      <description>... Congrats, Ken! (We are playing leap-frog on this one:-) Did you sieve k=1..250million, or what? Any other stats on your run? -Mike Oakes</description>
    </item>
    <item>
      <title>New Ap6 Record</title>
      <pubDate>Wed, 18 Nov 2009 05:49:17 GMT</pubDate>
      <dc:creator>kraDen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9824</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9824</guid>
      <description>Hi All (19303382 + $n*41724940)*5011#&#43;1 (n=0-5) describes an AP6 of 2152-2153 digit primes. cheers Ken Primality testing (19303382 + 0*41724940)*5011#&#43;1 [N-1,</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 05:44:20 GMT</pubDate>
      <dc:creator>Robin Garcia</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9823</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9823</guid>
      <description>&quot;By my records, Joe announced his at ... and I posted mine here at ... so assuming that both the clocks use GMT I missed out by almost an hour. This was an</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 05:41:53 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9822</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9822</guid>
      <description>... Joe pointed out, off list, that one of the 6 remaining quadratics can be factored by modifying the final cubic substitution. Let&#39;s look again at my 6</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 04:54:13 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9821</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9821</guid>
      <description>... http://users.cybercity.dk/~dsl522332/math/consecutive_factorizations.htm ... Thanks Jens. That&#39;s quite right and fair. By my records, Joe announced his at </description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 02:43:19 GMT</pubDate>
      <dc:creator>Jens Kruse Andersen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9820</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9820</guid>
      <description>... The Crump record was announced first and submitted first to me, so your nice 641-digit case for k=8 is not listed in the record history at </description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 703-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 01:01:28 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9819</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9819</guid>
      <description>... I meant to say GMP-ECM + GNFS. The largest GNFS dificulty, after GMP-ECM, was 117, which is not hard: http://homepage2.nifty.com/m_kamada/math/graphs.htm </description>
    </item>
    <item>
      <title>Factorization of 8 consecutive 703-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 00:46:02 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9818</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9818</guid>
      <description>... Aha, I have just seen that the Crump team has used my Ansatz to go up to 703 digits: http://immortaltheory.com/cnt/c703.html They were prepared for SNFS</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Wed, 18 Nov 2009 00:03:52 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9817</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9817</guid>
      <description>... After using GMP-ECM to depth p35, I was left with a pair of composites, with 147 and 148 digits, at an SNFS difficulty of about 161 digits, which is rather</description>
    </item>
    <item>
      <title>Re: Factorization of 8 consecutive 641-digit numbers</title>
      <pubDate>Tue, 17 Nov 2009 22:27:24 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primeform/message/9816</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primeform/message/9816</guid>
      <description>... It&#39;s a sextic for the benefit of SNFS. For most purposes we only need the fact that it is a quadratic in v = w^3. I found it by taking the 12 roots R[k] of</description>
    </item>

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