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    <title>primenumbers at Yahoo! Groups</title>
    <link>http://tech.groups.yahoo.com/group/primenumbers/</link>
    <description>Prime numbers and primality testing</description>

    <item>
      <title>2b. Re: Composite number function(2)</title>
      <pubDate>Fri, 20 Nov 2009 15:00:07 GMT</pubDate>
      <dc:creator>Kermit Rose</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21124</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21124</guid>
      <description>2b. Re: Composite number function(2) Posted by: &quot;djbroadhurst&quot; d.broadhurst@... djbroadhurst Date: Thu Nov 19, 2009 9:10 pm ((PST)) ... Hello David. ...</description>
    </item>
    <item>
      <title>Re: Composite number function(2)</title>
      <pubDate>Fri, 20 Nov 2009 05:10:25 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21123</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21123</guid>
      <description>... Post hoc, ergo propter hoc? ... Your nebulous &quot;algorithm&quot; was surpassed 2200 years ago: http://www.gap-system.org/~history/Biographies/Eratosthenes.html </description>
    </item>
    <item>
      <title>Composite number function(2)</title>
      <pubDate>Fri, 20 Nov 2009 04:40:35 GMT</pubDate>
      <dc:creator>Kermit Rose</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21122</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21122</guid>
      <description>1a. Re: Composite integer function Posted by: &quot;Yann Guidon&quot; whygee@... yasep16 Date: Wed Nov 18, 2009 9:02 am ((PST)) Hello Kermit, it seems that my</description>
    </item>
    <item>
      <title>Re: 2^a*3^b one away from a prime</title>
      <pubDate>Fri, 20 Nov 2009 04:33:22 GMT</pubDate>
      <dc:creator>marku606</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21121</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21121</guid>
      <description>... I think you&#39;re right Jens, infinitely many. By observation, the average number of solutions for a given prime seems to be roughly constant, around 10. For</description>
    </item>
    <item>
      <title>Re: 2^a*3^b one away from a prime</title>
      <pubDate>Thu, 19 Nov 2009 22:39:48 GMT</pubDate>
      <dc:creator>Jens Kruse Andersen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21120</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21120</guid>
      <description>... I expect infinitely many counter examples but there are none below 7500. I only computed one prime for each prime sum a&#43;b. -- Jens Kruse Andersen</description>
    </item>
    <item>
      <title>2^a*3^b one away from a prime</title>
      <pubDate>Thu, 19 Nov 2009 15:59:24 GMT</pubDate>
      <dc:creator>marku606</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21119</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21119</guid>
      <description>Given any prime expressed as a&#43;b, is there always some  a,b such that 2^a*3^b is one away from a prime? I doubt it but have yet to find a counterexample. Below</description>
    </item>
    <item>
      <title>Re: Composite integer function</title>
      <pubDate>Wed, 18 Nov 2009 17:02:43 GMT</pubDate>
      <dc:creator>Yann Guidon</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21118</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21118</guid>
      <description>Hello Kermit, it seems that my emails can&#39;t reach you due to some unexplainable blacklist on some router near you. So I answer on the list : ... &lt;snip&gt; ... can</description>
    </item>
    <item>
      <title>Composite integer function</title>
      <pubDate>Wed, 18 Nov 2009 00:16:54 GMT</pubDate>
      <dc:creator>Kermit Rose</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21117</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21117</guid>
      <description>You might be interested in the following two variable function. Define F(m,k) recursively as follows. F(1,1) = 15 F(m&#43;1,k) = F(m,k) + 4*(2*m + k + 2) F(m,k&#43;1)</description>
    </item>
    <item>
      <title>Re: How hard is it to find an AP-k?</title>
      <pubDate>Tue, 17 Nov 2009 19:50:27 GMT</pubDate>
      <dc:creator>mikeoakes2</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21116</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21116</guid>
      <description>... That was as per 6 Jun. Just over 5 months on, the revised table is:- rank k  d      s=(k&#43;4)*log(d) ... 1    8  1057   83.558 2    3  137514 82.817 3    12</description>
    </item>
    <item>
      <title></title>
      <pubDate>Sun, 15 Nov 2009 15:17:20 GMT</pubDate>
      <dc:creator>luis galup</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21115</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21115</guid>
      <description>David, you are absolutely correct, i misstated that conjecture. the conjecture asks whether o_p(2) = p-1 for infinitely many primes. this would correspond to </description>
    </item>
    <item>
      <title>Re: order of 2 in Z_p</title>
      <pubDate>Sun, 15 Nov 2009 11:49:29 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21114</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21114</guid>
      <description>... Counterexample: o_137(2) = (137 - 1)/2 = 68 o_p(2) is provably a divisor of p-1 for prime p. By the Artin conjecture, it is a proper divisor of p-1 for</description>
    </item>
    <item>
      <title>order of 2 in Z_p</title>
      <pubDate>Sun, 15 Nov 2009 08:44:55 GMT</pubDate>
      <dc:creator>LEGalup</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21113</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21113</guid>
      <description>Greetings all, let o_p(2) = order of 2 in F_p. in other words, o_p(2) = card{ 2^0 (mod p), 2^1 (mod p), ... , 2^p (mod p)  } we know that it is an open</description>
    </item>
    <item>
      <title>Re: New AP16 &amp; AP17 records</title>
      <pubDate>Sat, 14 Nov 2009 19:56:02 GMT</pubDate>
      <dc:creator>Jens Kruse Andersen</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21112</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21112</guid>
      <description>... Congratulations! http://users.cybercity.dk/~dsl522332/math/aprecords.htm is updated. That AP17 may last a while. I&#39;m not trying to retake it. -- Jens Kruse</description>
    </item>
    <item>
      <title>Finding a pair of Twin primes</title>
      <pubDate>Sat, 14 Nov 2009 18:36:45 GMT</pubDate>
      <dc:creator>mikeoakes2</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21111</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21111</guid>
      <description>I have just submitted to Chris&#39;s database a pair of primes that, at 25055 digits, will come in at rank 16 on his Top-20 Twins page </description>
    </item>
    <item>
      <title>Re: New AP16 &amp; AP17 records</title>
      <pubDate>Sat, 14 Nov 2009 16:33:00 GMT</pubDate>
      <dc:creator>djbroadhurst</dc:creator>
      <link>http://tech.groups.yahoo.com/group/primenumbers/message/21110</link>
      <guid isPermaLink="true">http://tech.groups.yahoo.com/group/primenumbers/message/21110</guid>
      <description>... That is, indeed, rather pleasing. Best regards, David</description>
    </item>

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