http://tech.groups.yahoo.com/group/probability/ Probability Tutorials Wed, 13 Dec 2006 07:01:25 GMT Shoaib Mukhtar http://tech.groups.yahoo.com/group/probability/message/1638 http://tech.groups.yahoo.com/group/probability/message/1638 Hi. This is Shoaib from Korea. I need your help in finding one solution. The problem explained as: Problem Statement I have to choose my best friend from the Wed, 22 Nov 2006 01:03:20 GMT mahe_iima http://tech.groups.yahoo.com/group/probability/message/1637 http://tech.groups.yahoo.com/group/probability/message/1637 ... new ... Hi If X >0, ie. X assumes only positive values and E(X) and E(1/X)exist then E(1/X)>= 1/E(X)because 1/X is a convex function. Wed, 22 Nov 2006 00:58:40 GMT wilsonwxwu http://tech.groups.yahoo.com/group/probability/message/1636 http://tech.groups.yahoo.com/group/probability/message/1636 THANK YOU VERY MUCH! Tue, 21 Nov 2006 00:44:16 GMT zak_hi79 http://tech.groups.yahoo.com/group/probability/message/1635 http://tech.groups.yahoo.com/group/probability/message/1635 ... I suggist to assume that y=1/x and make a transformation to this new r.v (y) and find f(y) then you can find the mean and variance. I will try to find it Mon, 20 Nov 2006 00:48:40 GMT krieck http://tech.groups.yahoo.com/group/probability/message/1634 http://tech.groups.yahoo.com/group/probability/message/1634 1) function of a random variable is a random variable 2) Assuming normality, use central limit theorem. ... From: MOMEYA To: probability@yahoogroups.com Sent: Thu, 16 Nov 2006 01:08:32 GMT MOMEYA http://tech.groups.yahoo.com/group/probability/message/1633 http://tech.groups.yahoo.com/group/probability/message/1633 please, if we have two sequences of independent random variable named Xn and Yn who tends in distribution to X and Y respectively, how can i show that Xn+Yn Thu, 09 Nov 2006 13:19:11 GMT sulli_melburn http://tech.groups.yahoo.com/group/probability/message/1632 http://tech.groups.yahoo.com/group/probability/message/1632 Note: question is not solved by me. It's solved by my colleage Asif well I think probability will be = (arrangements in which 3 diseased plants are Thu, 09 Nov 2006 13:12:08 GMT rraj@... http://tech.groups.yahoo.com/group/probability/message/1631 http://tech.groups.yahoo.com/group/probability/message/1631 In your approach, the first of three adjacent can be any one of 1-6, so there are 6 ways of having 3 adjacent plants with the disease. Similarly, the total Wed, 08 Nov 2006 02:00:21 GMT phigo67 http://tech.groups.yahoo.com/group/probability/message/1630 http://tech.groups.yahoo.com/group/probability/message/1630 here's the problem, In a small garden, there is a row of 8 pepper plants, 3 of which are diseased. Assuming that the disease occurs at random in the plants, Mon, 30 Oct 2006 17:51:31 GMT rraj@... http://tech.groups.yahoo.com/group/probability/message/1629 http://tech.groups.yahoo.com/group/probability/message/1629 Let the player decide to stay with probability p(x), when x (in 1-6) is obtained on the dice. In case the person stays, the chances of winning are x/6. Hence Mon, 30 Oct 2006 14:44:08 GMT tjankus http://tech.groups.yahoo.com/group/probability/message/1628 http://tech.groups.yahoo.com/group/probability/message/1628 Hi all :-) i was programming an AI for a game and got stuck with one problem. I don't know if you will be willing to help me, but i'll give it a try :-) it Mon, 09 Oct 2006 03:33:23 GMT sunitatrp http://tech.groups.yahoo.com/group/probability/message/1627 http://tech.groups.yahoo.com/group/probability/message/1627 the screw produced by a certain machine were checked by examining the number of defectives in a sample of 12. the folowing table shows the distribution of 128. Wed, 04 Oct 2006 15:16:51 GMT wilson wu http://tech.groups.yahoo.com/group/probability/message/1626 http://tech.groups.yahoo.com/group/probability/message/1626 Excuse me. I have worked this question several days. Assume X follow a NORMAL distribution with mean A and variance B, how to find the the mean and variance of Wed, 04 Oct 2006 15:09:09 GMT wilsonwxwu http://tech.groups.yahoo.com/group/probability/message/1625 http://tech.groups.yahoo.com/group/probability/message/1625 Excuse me. I have worked this question several days. Assume X follow a NORMAL distribution with mean A and variance B, how to find the the mean and variance of Mon, 25 Sep 2006 13:37:46 GMT gerard_faurejr http://tech.groups.yahoo.com/group/probability/message/1624 http://tech.groups.yahoo.com/group/probability/message/1624 The field f(A) generated by a class A in Omega is defined as the intersection of all fields in Omega containing A. (a)Show that f(A) is indeed a field, that A